package com.cn.designpatterns.ex.team;

/**
 *
 * 给定一个整数数组 nums 和一个目标值 target，请你在该数组中找出和为目标值的那 两个 整数，并返回他们的数组下标。
 *
 * 你可以假设每种输入只会对应一个答案。但是，你不能重复利用这个数组中同样的元素。
 *
 * 示例:
 *
 * 给定 nums = [2, 7, 11, 15], target = 9
 *
 * 因为 nums[0] + nums[1] = 2 + 7 = 9
 * 所以返回 [0, 1]
 *
 * @author: zhangyi
 * @date: 2019/1/7 22:24
 * @description:
 */
public class TwoNumber {

    public static void main(String[] args) {
        int[] nums = {3,2,4};
        int target = 6;
        Solution solution = new Solution();
        int[] ints = solution.twoSum(nums, target);
        StringBuffer stringBuffer = new StringBuffer();
        stringBuffer.append("[");
        int count = 0;
        for(int i : ints){
            stringBuffer.append(i);
            if(++count != ints.length){
                stringBuffer.append(",");
            }
        }
        stringBuffer.append("]");
        System.out.println(stringBuffer.toString());
    }
}
class Solution {

    public int[] twoSum(int[] nums, int target) {
        int sum = 0;
        int[] result = new int[2];
        for(int i = 0; i < nums.length;i++) {
            for (int j = i+1; j < nums.length; j++) {
                sum = nums[i] + nums[j];
                if(sum == target){
                    result[0] = i;
                    result[1] = j;
                    break;
                }
            }
            if (sum == target){
                break;
            }
        }
        return result;
    }
}